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Equation 131 · Part 9 · The Entry a Relabeling Cannot Write

fraction

Hc(t)=Hf+iℏ(iωr2σz)=ℏ(ω0−ωr)2σz,H_c(t) = H_f + i\hbar\Big(i\frac{\omega_r}{2}\sigma_z\Big) = \frac{\hbar(\omega_0 - \omega_r)}{2}\sigma_z,
fraction

What this part means

Divide the expression above the line by the one below it.

Its job in the formula

The expression above the fraction bar is divided by the complete expression below it. The denominator must not be zero.

The passage around this formula

A single case makes the term concrete and ties it to a result nearly a century old. Let HfH_f = (ℏ\hbarω0\omega_0/2)σz\sigma_z , a spin precessing about a static field at its Larmor frequency, and let U(t) = exp⁡(iωrt σz/2)\exp(i\omega_r t\,\sigma_z/2) describe a frame rotating about the same axis at rate ωr\omega_r . Since U(t) is built entirely from σz\sigma_z , it commutes with HfH_f , so UHfH_fU†U^\dagger = HfH_f exactly and the bare conjugate is unchanged by the relabeling. But U˙\dot U U†U^\dagger = iωr\omega_rσz\sigma_z/2 exactly, giving Hc(t)=Hf+iℏ(iωr2σz)=ℏ(ω0−ωr)2σzH_c(t) = H_f + i\hbar\Big(i\frac{\omega_r}{2}\sigma_z\Big) = \frac{\hbar(\omega_0 - \omega_r)}{2}\sigma_z. the detuned Hamiltonian that governs spin precession in a frame rotating with an applied field — the identical construction I. I. Rabi used to analyze spin behavior in a…

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Learn the underlying idea

A fraction a/b means a divided by b. The top number is the numerator; the bottom number is the denominator, and it cannot be zero.

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Sources cited in the surrounding passage

These citations provide research context; check each source for the exact claim it supports.