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Equation 131 · Part 8 · The Entry a Relabeling Cannot Write

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Hc(t)=Hf+iℏ(iωr2σz)=ℏ(ω0−ωr)2σz,H_c(t) = H_f + i\hbar\Big(i\frac{\omega_r}{2}\sigma_z\Big) = \frac{\hbar(\omega_0 - \omega_r)}{2}\sigma_z,
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What this part means

The expressions on both sides represent the same quantity under the stated assumptions.

Its job in the formula

The equals sign connects the complete expression on the left with the complete expression on the right. Both sides must have compatible units.

The passage around this formula

A single case makes the term concrete and ties it to a result nearly a century old. Let HfH_f = (ℏ\hbarω0\omega_0/2)σz\sigma_z , a spin precessing about a static field at its Larmor frequency, and let U(t) = exp⁡(iωrt σz/2)\exp(i\omega_r t\,\sigma_z/2) describe a frame rotating about the same axis at rate ωr\omega_r . Since U(t) is built entirely from σz\sigma_z , it commutes with HfH_f , so UHfH_fU†U^\dagger = HfH_f exactly and the bare conjugate is unchanged by the relabeling. But U˙\dot U U†U^\dagger = iωr\omega_rσz\sigma_z/2 exactly, giving Hc(t)=Hf+iℏ(iωr2σz)=ℏ(ω0−ωr)2σzH_c(t) = H_f + i\hbar\Big(i\frac{\omega_r}{2}\sigma_z\Big) = \frac{\hbar(\omega_0 - \omega_r)}{2}\sigma_z. the detuned Hamiltonian that governs spin precession in a frame rotating with an applied field — the identical construction I. I. Rabi used to analyze spin behavior in a…

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Learn the underlying idea

An equals sign says that the expression on its left and the expression on its right have the same value under the stated definitions and assumptions.

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Sources cited in the surrounding passage

These citations provide research context; check each source for the exact claim it supports.