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Equation 131 · Part 10 · The Entry a Relabeling Cannot Write

addition

Hc(t)=Hf+iℏ(iωr2σz)=ℏ(ω0−ωr)2σz,H_c(t) = H_f + i\hbar\Big(i\frac{\omega_r}{2}\sigma_z\Big) = \frac{\hbar(\omega_0 - \omega_r)}{2}\sigma_z,
addition

What this part means

Add the term after the plus sign to the term or group before it.

Its job in the formula

Add the term after the plus sign to the term or group before it.

The passage around this formula

A single case makes the term concrete and ties it to a result nearly a century old. Let HfH_f = (ℏ\hbarω0\omega_0/2)σz\sigma_z , a spin precessing about a static field at its Larmor frequency, and let U(t) = exp⁡(iωrt σz/2)\exp(i\omega_r t\,\sigma_z/2) describe a frame rotating about the same axis at rate ωr\omega_r . Since U(t) is built entirely from σz\sigma_z , it commutes with HfH_f , so UHfH_fU†U^\dagger = HfH_f exactly and the bare conjugate is unchanged by the relabeling. But U˙\dot U U†U^\dagger = iωr\omega_rσz\sigma_z/2 exactly, giving Hc(t)=Hf+iℏ(iωr2σz)=ℏ(ω0−ωr)2σzH_c(t) = H_f + i\hbar\Big(i\frac{\omega_r}{2}\sigma_z\Big) = \frac{\hbar(\omega_0 - \omega_r)}{2}\sigma_z. the detuned Hamiltonian that governs spin precession in a frame rotating with an applied field — the identical construction I. I. Rabi used to analyze spin behavior in a…

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Learn the underlying idea

Addition combines quantities; subtraction measures the signed difference between them. Parentheses show what is combined before the rest of the expression is evaluated.

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Sources cited in the surrounding passage

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