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Equation 10 · Part 1 · What Interpretability Actually Costs to Do at Scale

Symbol d

2dn2dn
dd

What this part means

d is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

Its job in the formula

d is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

The passage around this formula

Work out what that architecture actually spends compute on per token, because the two halves of it behave differently. The encoding step needs a score for every one of the n candidate latents before it can select the top k , so it is an unavoidably dense matrix multiply: roughly 2dn floating-point operations. The decoding step only touches the k latents that survived, so it is sparse: roughly 2dk operations. Summed and multiplied across T training tokens, a first-order compute model for training the dictionary is

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A variable is a named place for a value. Its letter is a local label: x can mean position in one formula and a data point in another.

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