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Equation 1 · One Gene, Forty Eyes: What Evo-Devo Did to the Convergence Story

What does this equation mean?

h2×i×V=0.50×0.01×0.01=0.00005h^2 \times i \times V = 0.50 \times 0.01 \times 0.01 = 0.00005

Read the formula alongside the article passage below. Each part has a deeper page with its role in the equation, the supporting passage and nearby citations.

Inputs and operations0.50 × 0.01 × 0.01 = 0.00005
Result or conditionh^2 × i × V
How to read the two sides of this formula. Follow the article passage for the meaning of each quantity.

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions. Read the equation part by part below; each part has a contextual explanation and a link to its mathematical background.

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h2h^2

Symbol h^2

The square of h: multiply h by itself.

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ii

Symbol i

i is part of the quantity the equation computes from the expression on the right.

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VV

Symbol V

V is part of the quantity the equation computes from the expression on the right.

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=

=

The expressions on both sides represent the same quantity under the stated assumptions.

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multiplication

multiplication

Multiply the quantities on either side.

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superscript

superscript

A raised number can be a power. When it is a label or bound, it selects a case or the upper limit of a sum; the formula’s structure distinguishes these uses.

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How to interpret it

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What the article says around this equation

To convert steps into generations, Nilsson and Pelger applied the standard quantitative-genetics equation for the response to selection on a continuous trait, deliberately choosing pessimistic values for every free parameter: a heritability of 0.50, a selection intensity of 0.01, and a coefficient of phenotypic variation of 0.01, values the authors describe as common or deliberately conservative rather than favourable to a fast result [ 4 ] . Those choices give a fractional improvement of only 0.005 percent of the trait mean per generation. Compounding that per-generation rate to reach the full 1,829 steps of one-percent change — equivalent to a single structure lengthening by a factor of…
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To convert steps into generations, Nilsson and Pelger applied the standard quantitative-genetics equation for the response to selection on a continuous trait, deliberately choosing pessimistic values for every free parameter: a heritability of 0.50, a selection intensity of 0.01, and a coefficient of phenotypic variation of 0.01, values the authors describe as common or deliberately conservative rather than favourable to a fast result [ 4 ] . Those choices give a fractional improvement of only 0.005 percent of the trait mean per generation. Compounding that per-generation rate to reach the full 1,829 steps of one-percent change — equivalent to a single structure lengthening by a factor of just over eighty million — requires solving:

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Sources cited in the surrounding passage

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