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Equation 2 · Hominin Evolution and Deep Prehistory: A First-Principles Introduction

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f^=∑i(P2(i)−P1(i)) (P4(i)−P1(i))∑i(P3(i)−P1(i)) (P4(i)−P1(i))\hat{f} = \frac{\sum_{i} (P_2(i) - P_1(i))\,(P_4(i) - P_1(i))}{\sum_{i} (P_3(i) - P_1(i))\,(P_4(i) - P_1(i))}

Read the formula alongside the article passage below. Each part has a deeper page with its role in the equation, the supporting passage and nearby citations.

Start withsum_i (P_2(i) - P_1(i))(P_4(i) - P_1(i))
Divide bysum_i (P_3(i) - P_1(i))(P_4(i) - P_1(i))
This relates tohatf
How to read the two sides of this formula. Follow the article passage for the meaning of each quantity.

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions. Read the equation part by part below; each part has a contextual explanation and a link to its mathematical background.

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f^\hat{f}

Symbol hatf

hatf is part of the quantity the equation computes from the expression on the right.

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ii

Symbol i

i appears in the bound of this sum. The bound states where the repeated operation starts, ends, or which values it includes.

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P2P_2

Symbol P_2

P2P_2 occurs above the fraction bar. The numerator is divided by the entire denominator below it.

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P1P_1

Symbol P_1

P1P_1 is one of the signed contributions combined to compute the quantity on the left.

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P4P_4

Symbol P_4

P4P_4 is one of the signed contributions combined to compute the quantity on the left.

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P3P_3

Symbol P_3

P3P_3 occurs below the fraction bar. The quantity above the bar is divided by this expression; zero is excluded as a denominator.

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=

=

The expressions on both sides represent the same quantity under the stated assumptions.

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fraction

fraction

Divide the expression above the line by the one below it.

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subtraction

subtraction

Subtract the following term or group from the preceding one. A leading minus marks a negative quantity.

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subscript

subscript

The lower label selects a particular version, component, or indexed member of the quantity. For example, x₀ and xₜ can be values at different positions.

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∑i(P2(i)−P1(i)) (P4(i)−P1(i))\sum_{i} (P_2(i) - P_1(i))\,(P_4(i) - P_1(i))

Numerator: sum_i (P_2(i) - P_1(i))(P_4(i) - P_1(i))

The complete quantity above the fraction bar.

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∑i(P3(i)−P1(i)) (P4(i)−P1(i))\sum_{i} (P_3(i) - P_1(i))\,(P_4(i) - P_1(i))

Denominator: sum_i (P_3(i) - P_1(i))(P_4(i) - P_1(i))

The complete quantity below the fraction bar; it must be nonzero for this division.

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ii

Starting index or lower bound: i

This label says where the repeated addition, multiplication, or accumulation starts. Read its value or condition together with the article’s description of the index.

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ii

Starting index or lower bound: i

This label says where the repeated addition, multiplication, or accumulation starts. Read its value or condition together with the article’s description of the index.

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How to interpret it

With a fixed numerator, increasing a nonzero denominator reduces the fraction. Read it with the definitions, units, and assumptions supplied by the article.

What the article says around this equation

The basic tool for estimating what fraction of a genome derives from an archaic population is comparative allele sharing: for a given modern population, count how much more genetic variation it shares with an archaic genome than a population known to lack that admixture does, and scale by how much variation the archaic and comparison genomes share with each other overall. A simplified version of the widely used D -statistic framework expresses this as: f^=∑i(P2(i)−P1(i)) (P4(i)−P1(i))∑i(P3(i)−P1(i)) (P4(i)−P1(i))\hat{f} = \frac{\sum_{i} (P_2(i) - P_1(i))\,(P_4(i) - P_1(i))}{\sum_{i} (P_3(i) - P_1(i))\,(P_4(i) - P_1(i))}. where P1P_1 through P4P_4 are allele frequencies at site i in an outgroup, a candidate-admixed population, a comparison population without the admixture, and the archaic source, respectively. The estimator exploits a simple…
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The basic tool for estimating what fraction of a genome derives from an archaic population is comparative allele sharing: for a given modern population, count how much more genetic variation it shares with an archaic genome than a population known to lack that admixture does, and scale by how much variation the archaic and comparison genomes share with each other overall. A simplified version of the widely used D -statistic framework expresses this as: f^=∑i(P2(i)−P1(i)) (P4(i)−P1(i))∑i(P3(i)−P1(i)) (P4(i)−P1(i))\hat{f} = \frac{\sum_{i} (P_2(i) - P_1(i))\,(P_4(i) - P_1(i))}{\sum_{i} (P_3(i) - P_1(i))\,(P_4(i) - P_1(i))}. where P1P_1 through P4P_4 are allele frequencies at site i in an outgroup, a candidate-admixed population, a comparison population without the admixture, and the archaic source, respectively. The estimator exploits a simple logic: if population P2P_2 has interbred with the archaic lineage P4P_4 and P3P_3 has not, P2P_2 should share systematically more rare variants with P4P_4 than P3P_3 does, in proportion to the fraction of its genome that traces to that admixture event. This is why admixture claims in the literature are reported as percentages with confidence intervals rather than as a binary yes/no — the estimate is statistical, built from many thousands of sites, not read off a single marker.

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