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Equation 2 · Part 13 · Hominin Evolution and Deep Prehistory: A First-Principles Introduction

Starting index or lower bound: i

f^=∑i(P2(i)−P1(i)) (P4(i)−P1(i))∑i(P3(i)−P1(i)) (P4(i)−P1(i))\hat{f} = \frac{\sum_{i} (P_2(i) - P_1(i))\,(P_4(i) - P_1(i))}{\sum_{i} (P_3(i) - P_1(i))\,(P_4(i) - P_1(i))}
ii

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This label says where the repeated addition, multiplication, or accumulation starts. Read its value or condition together with the article’s description of the index.

Its job in the formula

i appears in the bound of this sum. The bound states where the repeated operation starts, ends, or which values it includes.

The passage around this formula

…archaic and comparison genomes share with each other overall. A simplified version of the widely used D -statistic framework expresses this as: f^=∑i(P2(i)−P1(i)) (P4(i)−P1(i))∑i(P3(i)−P1(i)) (P4(i)−P1(i))\hat{f} = \frac{\sum_{i} (P_2(i) - P_1(i))\,(P_4(i) - P_1(i))}{\sum_{i} (P_3(i) - P_1(i))\,(P_4(i) - P_1(i))}. where P1P_1 through P4P_4 are allele frequencies at site i in an outgroup, a candidate-admixed population, a comparison population without the admixture, and the archaic source, respectively. The estimator exploits a simple logic: if population P2P_2 has interbred with the archaic lineage P4P_4 and P3P_3 has not, P2P_2 should share systematically more rare…

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