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Equation 90 · The Entry a Relabeling Cannot Write

What does this equation mean?

⟨e,g∣Hf∣e,g⟩=ℏω/2−ℏω/2+0=0\langle e,g|H_f|e,g\rangle = \hbar\omega/2 - \hbar\omega/2 + 0 = 0

Read the formula alongside the article passage below. Each part has a deeper page with its role in the equation, the supporting passage and nearby citations.

Inputs and operationshbaromega/2 - hbaromega/2 + 0 = 0
Result or conditionlangle e,g|H_f|e,grangle
How to read the two sides of this formula. Follow the article passage for the meaning of each quantity.

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions. Read the equation part by part below; each part has a contextual explanation and a link to its mathematical background.

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ee

Symbol e

e is part of the quantity the equation computes from the expression on the right.

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gg

Symbol g

g is part of the quantity the equation computes from the expression on the right.

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HfH_f

Symbol H_f

HfH_f is part of the quantity the equation computes from the expression on the right.

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ω\omega

Symbol omega

omega is one of the signed contributions combined to compute the quantity on the left.

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=

=

The expressions on both sides represent the same quantity under the stated assumptions.

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addition

addition

Add the term after the plus sign to the term or group before it.

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subtraction

subtraction

Subtract the following term or group from the preceding one. A leading minus marks a negative quantity.

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subscript

subscript

The lower label selects a particular version, component, or indexed member of the quantity. For example, x₀ and xₜ can be values at different positions.

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How to interpret it

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What the article says around this equation

the standard two-level exchange solution, exact for all t under this Hamiltonian. From it, ⟨\langle HSH_S ⟩(t)\rangle(t) = (ℏ\hbarω\omega/2)[cos⁡2(gt)\cos^2(gt) - sin⁡2(gt)\sin^2(gt)] = (ℏ\hbarω\omega/2)cos⁡(2gt)\cos(2gt) , while ⟨\langle HfH_f ⟩\rangle is exactly time-independent — a general fact for any state evolving under its own generator, not special to this one — and equal here to ⟨\langle e,g|HfH_f|e,g⟩\rangle = ℏ\hbarω\omega/2 - ℏ\hbarω\omega/2 + 0 = 0 , since HSBH_{SB} is purely off-diagonal in this basis. The ledger reading follows immediately:

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