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Equation 104 · Part 1 · The Entry a Relabeling Cannot Write

Symbol t^ast

t∗=π/(2g)=1/(4×10 MHz)=25.0 nst^\ast = \pi/(2g) = 1/(4\times10\ \mathrm{MHz}) = 25.0\ \mathrm{ns}
t∗t^\ast

What this part means

tat^ast is part of the quantity the equation computes from the expression on the right.

Its job in the formula

tat^ast is part of the quantity the equation computes from the expression on the right.

The passage around this formula

…circuit quantum electrodynamics architectures, which span a few gigahertz in frequency and from a fraction of a megahertz up to several hundred megahertz in coupling depending on the regime [ 12 ] . The swap time is t∗t^\ast = π\pi/(2g) = 1/(4×\times10\ MHz\mathrm{MHz}) = 25.0\ ns\mathrm{ns} , and the ledger’s swing at that instant is ℏ\hbarω\omega/2 ≈\approx 1.66×\times10^{-24}\ J\mathrm{J} ≈\approx 10.3\ μ\mueV\mathrm{eV} — an exact analytic evaluation under the stated resonance and coupling assumptions, reported here as…

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An exponent tells how a base is used in multiplication. In x³, x is the base and 3 is the exponent: x³ = x × x × x.

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