Symbol K

The passage around this formula

…with $\gamma$ of order 2$\times$10^5 and r of order several kilometers, this works out to a $\sim$ 8$\times$10^{23}\,$\mathrm{m\,s^{-2}}$ , corresponding by the Unruh formula to $T_U$ = $\hbar$ a/(2$\pi$ c $k_B$) $\sim$ 3$\times$10^3\,$\mathrm K$ — a temperature scale that is, remarkably, not astronomically small, unlike the roughly 10^{-19}\,$\mathrm K$ an Earth-bound laboratory accelerometer would need a planet’s worth of gravity to approach. Bell and Leinaas pointed out that the relevant observable is not a literal thermometer reading…

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