Published equation contexts

$t_L/\beta \approx 28.2$

Why this formula appears here

A third, more uncomfortable check is what the toy model of the previous section actually implies at the numbers already computed: $t_L$ $\approx$ 3.5\, $\mathrm{ms}$ , or $t_L$ / $\beta$ $\approx$ 28.2 , for the solar-mass hole above. Taking $f_1$ = 1 as an illustrative, explicitly assumed per-quantum information content, a modest tolerance $\delta$ = 0.1\, $\mathrm{rad}$ (about six degrees) gives $t_G$ / $\beta$ = 100 , so $t_G$ $\approx$ 12.4\, $\mathrm{ms}$ and $\Delta$ $t_{LG}$ $\approx$ +8.9\, $\mathrm{ms}$ : the compass is the slower debt, as the title claims. But a coarser tolerance, $\delta$ = 0.5\, $\mathrm{rad}$ (about twenty-nine degrees), gives $t_G$ / $\beta$ = 4 , so $t_G$ $\approx$ 0.50\, $\mathrm{ms}$ and $\Delta$ $t_{LG}$ $\approx$ …

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t_L

Symbol t_L

$t_L$ is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

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\beta

Symbol β

β is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

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Its accuracy depends on the assumptions and range of use described in the article.

Research cited beside this formula

[11] Superselection Rules and Quantum Protocols ↗

Published contexts (1)

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t_L/\beta \approx 28.2

Equation 119 · Evolutionary Physics

The Bit Comes Back Before the Bearing

This equation gives an approximation: it relates the quantities while allowing an approximation.

A third, more uncomfortable check is what the toy model of the previous section actually implies at the numbers already computed: $t_L$ $\approx$ 3.5\, $\mathrm{ms}$ , or $t_L$ / $\beta$ $\approx$ 28.2 , for the solar-mass hole above. Taking $f_1$ = 1 as an illustrative, explicitly assumed per-quantum information content, a modest tolerance $\delta$ = 0.1\, $\mathrm{rad}$ (about six degrees) gives $t_G$ / $\beta$ = 100 , so $t_G$ $\approx$ 12.4\, $\mathrm{ms}$ and $\Delta$ $t_{LG}$ $\approx$ +8.9\, $\mathrm{ms}$ : the compass is the slower debt, as the title claims. But a coarser tolerance, $\delta$ = 0.5\, $\mathrm{rad}$ (about twenty-nine degrees), gives $t_G$ / $\beta$ = 4 , so $t_G$ $\approx$ 0.50\, $\mathrm{ms}$ and $\Delta$ $t_{LG}$ $\approx$ …

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tL/β≈28.2t_L/\beta \approx 28.2tL​/β≈28.2