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Published equation contexts

⟨e−βW⟩=e−βΔF,β=1kBT\left\langle e^{-\beta W} \right\rangle = e^{-\beta \Delta F}, \qquad \beta = \frac{1}{k_{\mathrm{B}} T}

Why this formula appears here

Christopher Jarzynski’s 1997 equality was the opening result. For a system beginning in thermal equilibrium and then driven away from it by an arbitrarily fast, arbitrarily far-from-equilibrium protocol, the exponential average of the work W performed on it recovers the equilibrium free-energy difference Δ\Delta F between the protocol’s start and end points exactly: ⟨e−βW⟩=e−βΔF,β=1kBT\left\langle e^{-\beta W} \right\rangle = e^{-\beta \Delta F}, \qquad \beta = \frac{1}{k_{\mathrm{B}} T}. [ 5 ] . The result does not say average work equals Δ\Delta F — dissipation makes the ordinary average of W larger than Δ\Delta F whenever the protocol is not quasistatic — it says a specific nonlinear average of a driven, dissipative, irreversible process reproduces an equilibrium quantity exactly, which is a…

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e−βWe^{-\beta W}

Symbol e^-β W

e−e^-β W is part of the quantity the equation computes from the expression on the right.

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e−βΔFe^{-\beta \Delta F}

Symbol e^-β Δ F

e−e^-β Δ F is one of the signed contributions combined to compute the quantity on the left.

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kBk_{\mathrm{B}}

Symbol k_B

kBk_B occurs below the fraction bar. The quantity above the bar is divided by this expression; zero is excluded as a denominator.

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TT

Symbol T

T occurs below the fraction bar. The quantity above the bar is divided by this expression; zero is excluded as a denominator.

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kBTk_{\mathrm{B}} T

Denominator: k_B T

The complete quantity below the fraction bar; it must be nonzero for this division.

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How to interpret it

With a fixed numerator, increasing a nonzero denominator reduces the fraction. Read it with the definitions, units, and assumptions supplied by the article.

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Published contexts (1)

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⟨e−βW⟩=e−βΔF,β=1kBT\left\langle e^{-\beta W} \right\rangle = e^{-\beta \Delta F}, \qquad \beta = \frac{1}{k_{\mathrm{B}} T}

Equation 6 · Evolutionary Physics

The Arrow of Time and the Engine of Evolution

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

Christopher Jarzynski’s 1997 equality was the opening result. For a system beginning in thermal equilibrium and then driven away from it by an arbitrarily fast, arbitrarily far-from-equilibrium protocol, the exponential average of the work W performed on it recovers the equilibrium free-energy difference Δ\Delta F between the protocol’s start and end points exactly: ⟨e−βW⟩=e−βΔF,β=1kBT\left\langle e^{-\beta W} \right\rangle = e^{-\beta \Delta F}, \qquad \beta = \frac{1}{k_{\mathrm{B}} T}. [ 5 ] . The result does not say average work equals Δ\Delta F — dissipation makes the ordinary average of W larger than Δ\Delta F whenever the protocol is not quasistatic — it says a specific nonlinear average of a driven, dissipative, irreversible process reproduces an equilibrium quantity exactly, which is a…

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