Symbol k
one of the few published metrics designed to recover it, and its scarcity elsewhere in this literature is itself a gap in the evidence.
Read this term in its guide →Published equation contexts
That gap is large enough to be worth writing down explicitly. If a task’s outcome were an independent Bernoulli draw with a fixed success probability p equal to the reported average, the probability that all k independent attempts at the same task succeed would be . At p = 0.60 and k = 8 , that model predicts roughly 1.7%. The reported figure — under 25% — sits well above that naive prediction, and the direction of the gap is informative on its own: it is only possible if outcomes are not independent draws from one fixed probability, but rather reflect a task population that splits into instances the agent reliably solves and instances it reliably does not, with the…
one of the few published metrics designed to recover it, and its scarcity elsewhere in this literature is itself a gap in the evidence.
Read this term in its guide →is an input to the expression that computes the quantity on the left.
Read this term in its guide →The probability operator gives the chance of the event named inside its brackets or parentheses.
Read this term in its guide →Read it with the definitions, units, and assumptions supplied by the article.
A symbol can carry a different meaning in another article. Each occurrence keeps its own guide and term definitions.
Equation 3 · AI Infrastructure
This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.
That gap is large enough to be worth writing down explicitly. If a task’s outcome were an independent Bernoulli draw with a fixed success probability p equal to the reported average, the probability that all k independent attempts at the same task succeed would be . At p = 0.60 and k = 8 , that model predicts roughly 1.7%. The reported figure — under 25% — sits well above that naive prediction, and the direction of the gap is informative on its own: it is only possible if outcomes are not independent draws from one fixed probability, but rather reflect a task population that splits into instances the agent reliably solves and instances it reliably does not, with the…