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Λ†:B(Hc)→B(Hf)\Lambda^\dagger: \mathcal B(\mathcal H_c) \to \mathcal B(\mathcal H_f)

Why this formula appears here

Every channel has a dual. Define Λ†\Lambda^\dagger: B(Hc)\mathcal B(\mathcal H_c) →\to B(Hf)\mathcal B(\mathcal H_f) by the pairing that must hold for every fine state and every coarse observable OcO_c ,

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BB

Symbol B

B is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

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HcH_c

Symbol H_c

wrong, does not touch the total energy of any closed system, and does not by itself explain where a nonzero reading comes from.

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HfH_f

Symbol H_f

HfH_f is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

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Published contexts (1)

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Λ†:B(Hc)→B(Hf)\Lambda^\dagger: \mathcal B(\mathcal H_c) \to \mathcal B(\mathcal H_f)

Equation 12 · Evolutionary Physics

The Entry a Relabeling Cannot Write

This mathematical expression combines the displayed quantities; its precise role follows from the surrounding article text.

Every channel has a dual. Define Λ†\Lambda^\dagger: B(Hc)\mathcal B(\mathcal H_c) →\to B(Hf)\mathcal B(\mathcal H_f) by the pairing that must hold for every fine state and every coarse observable OcO_c ,

Meanings in this article

  • Λ†\Lambda^\dagger: the define.
  • HcH_c: wrong, does not touch the total energy of any closed system, and does not by itself explain where a nonzero reading comes from.
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