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Λ†(HS)=HS⊗IB\Lambda^\dagger(H_S) = H_S \otimes I_B

Why this formula appears here

Return to the genuine coarse-graining set aside earlier: Λ(ρ)\Lambda(\rho) = TrB\mathrm{Tr}_B[ρ\rho] , Hc\mathcal H_c = HS\mathcal H_S , HcH_c = HSH_S . The dual embeds a system observable back into the full space without touching the bath, Λ†(HS)\Lambda^\dagger(H_S) = HSH_S ⊗\otimes IBI_B , so

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Λ†\Lambda^\dagger

Symbol Lambda^dagger

Lambdada^dagger is part of the quantity the equation computes from the expression on the right.

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HSH_S

Symbol H_S

HSH_S is an argument of the function-like quantity on the left; its role is set by that function’s stated inputs.

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Published contexts (1)

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Λ†(HS)=HS⊗IB\Lambda^\dagger(H_S) = H_S \otimes I_B

Equation 60 · Evolutionary Physics

The Entry a Relabeling Cannot Write

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

Return to the genuine coarse-graining set aside earlier: Λ(ρ)\Lambda(\rho) = TrB\mathrm{Tr}_B[ρ\rho] , Hc\mathcal H_c = HS\mathcal H_S , HcH_c = HSH_S . The dual embeds a system observable back into the full space without touching the bath, Λ†(HS)\Lambda^\dagger(H_S) = HSH_S ⊗\otimes IBI_B , so

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