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ΔE/E≈veq/c=2πνR/c≈1.3×10−1(ν/500 Hz)(R/12 km)\Delta E/E \approx v_{eq}/c = 2\pi\nu R/c \approx 1.3\times10^{-1}(\nu/500\,\text{Hz})(R/12\,\text{km})

Why this formula appears here

The mechanism behind that contradiction is simple enough to state in one line, and the paper’s authors compute it carefully because the commonly quoted version understates it by an order of magnitude. Surface rotation Doppler-broadens any spectral line by a fraction of its energy equal to the star’s equatorial velocity over the speed of light, Δ\Delta E/E ≈\approx veqv_{eq}/c = 2π\piν\nu R/c ≈\approx 1.3×\times10^{-1}(ν\nu/500\,Hz\text{Hz})(R/12\,km\text{km}) , where ν\nu is the star’s spin frequency and R its radius.

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Published contexts (1)

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ΔE/E≈veq/c=2πνR/c≈1.3×10−1(ν/500 Hz)(R/12 km)\Delta E/E \approx v_{eq}/c = 2\pi\nu R/c \approx 1.3\times10^{-1}(\nu/500\,\text{Hz})(R/12\,\text{km})

Equation 20 · Crossed Fields

A Neutron Star Is a Redshift Standard

This equation gives an approximation: it relates the quantities while allowing an approximation.

The mechanism behind that contradiction is simple enough to state in one line, and the paper’s authors compute it carefully because the commonly quoted version understates it by an order of magnitude. Surface rotation Doppler-broadens any spectral line by a fraction of its energy equal to the star’s equatorial velocity over the speed of light, Δ\Delta E/E ≈\approx veqv_{eq}/c = 2π\piν\nu R/c ≈\approx 1.3×\times10^{-1}(ν\nu/500\,Hz\text{Hz})(R/12\,km\text{km}) , where ν\nu is the star’s spin frequency and R its radius.

Meanings in this article

  • ν\nu: the star’s spin frequency.
  • RR: the radius.
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