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[Ki,Pj]=iℏ m δij 1[K_i,P_j]=i\hbar\,m\,\delta_{ij}\,\mathbb 1

Why this formula appears here

They do not commute. The defining fact of the nonrelativistic symmetry group, established by Bargmann and sharpened by Lévy-Leblond, is that its faithful quantum representations require a centrally extended algebra in which [Ki,Pj]=iℏ m δij 1[K_i,P_j]=i\hbar\,m\,\delta_{ij}\,\mathbb 1. with mass m appearing not as an eigenvalue to be measured state by state but as a fixed number multiplying the identity operator across an entire representation [ 1 , 2 ] . This is what “central” means: the commutator commutes with everything, including K\mathbf K and P\mathbf P themselves.

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Published contexts (1)

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[Ki,Pj]=iℏ m δij 1,[K_i,P_j]=i\hbar\,m\,\delta_{ij}\,\mathbb 1,

Equation 27 · Evolutionary Physics

The Clock That Comes Back Wrong by Exactly Its Mass

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

They do not commute. The defining fact of the nonrelativistic symmetry group, established by Bargmann and sharpened by Lévy-Leblond, is that its faithful quantum representations require a centrally extended algebra in which [Ki,Pj]=iℏ m δij 1[K_i,P_j]=i\hbar\,m\,\delta_{ij}\,\mathbb 1. with mass m appearing not as an eigenvalue to be measured state by state but as a fixed number multiplying the identity operator across an entire representation [ 1 , 2 ] . This is what “central” means: the commutator commutes with everything, including K\mathbf K and P\mathbf P themselves.

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