← Mathematical compendium

Published equation contexts

En=εn(ℏ2mg2g22mi)1/3E_n = \varepsilon_n \left(\frac{\hbar^2 m_{g}^2 g^2}{2 m_{i}}\right)^{1/3}

Why this formula appears here

Above a perfectly reflecting mirror, a neutron’s Schrödinger equation is about as simple as a bound-state problem gets: an infinite wall at the mirror’s surface and a linear potential rising above it, gravity playing the same role a laser trap or a magnetic bottle plays in every other cold-atom experiment. The exact solutions are Airy functions, and the allowed energies are En=εn(ℏ2mg2g22mi)1/3E_n = \varepsilon_n \left(\frac{\hbar^2 m_{g}^2 g^2}{2 m_{i}}\right)^{1/3}. where εn\varepsilon_n is the n -th negative zero of the Airy function — 2.338, 4.088, 5.521, 6.787, and so on — and the mass has been split deliberately into a gravitational piece mgm_{g} , which sets how hard the potential pulls, and an inertial piece mim_{i} , which sets how the wavefunction spreads in…

Read the full article-specific guide →

Read the representative guide

mg2m_{g}^2

Symbol m_g^2

mg2m_g^2 occurs above the fraction bar. The numerator is divided by the entire denominator below it.

Read this term in its guide →

How to interpret it

With a fixed numerator, increasing a nonzero denominator reduces the fraction. Read it with the definitions, units, and assumptions supplied by the article.

Research cited beside this formula

Published contexts (1)

A symbol can carry a different meaning in another article. Each occurrence keeps its own guide and term definitions.

En=εn(ℏ2mg2g22mi)1/3E_n = \varepsilon_n \left(\frac{\hbar^2 m_{g}^2 g^2}{2 m_{i}}\right)^{1/3}

Equation 1 · Crossed Fields

The Oldest Quantum-Gravity Experiment Is a Neutron Falling

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

Above a perfectly reflecting mirror, a neutron’s Schrödinger equation is about as simple as a bound-state problem gets: an infinite wall at the mirror’s surface and a linear potential rising above it, gravity playing the same role a laser trap or a magnetic bottle plays in every other cold-atom experiment. The exact solutions are Airy functions, and the allowed energies are En=εn(ℏ2mg2g22mi)1/3E_n = \varepsilon_n \left(\frac{\hbar^2 m_{g}^2 g^2}{2 m_{i}}\right)^{1/3}. where εn\varepsilon_n is the n -th negative zero of the Airy function — 2.338, 4.088, 5.521, 6.787, and so on — and the mass has been split deliberately into a gravitational piece mgm_{g} , which sets how hard the potential pulls, and an inertial piece mim_{i} , which sets how the wavefunction spreads in…

Meanings in this article

Equation guide → · Article →