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DΛ=0D_\Lambda = 0

Why this formula appears here

is a real number in units of energy for every fine state ρ\rho : how much the coarse description, evaluated through HcH_c pulled back along Λ\Lambda , disagrees with the fine description’s own HfH_f , for that specific state. Because expectation values determine a Hermitian operator uniquely — two Hermitian operators with the same trace against every density matrix are the same operator — the strongest statement follows at once: Δ\Delta EΛ(ρ)E_\Lambda(\rho) = 0 for every fine state ρ\rho if and only if DΛD_\Lambda = 0 as an operator identity, that is, if and only if Λ†(Hc)\Lambda^\dagger(H_c) = HfH_f exactly. Energy is preserved for every possible input under that one algebraic condition, never as a statistical…

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DΛD_\Lambda

Symbol D_Lambda

DLD_Lambda is part of the quantity the equation computes from the expression on the right.

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Published contexts (2)

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DΛ=0D_\Lambda = 0

Equation 31 · Evolutionary Physics

The Entry a Relabeling Cannot Write

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

is a real number in units of energy for every fine state ρ\rho : how much the coarse description, evaluated through HcH_c pulled back along Λ\Lambda , disagrees with the fine description’s own HfH_f , for that specific state. Because expectation values determine a Hermitian operator uniquely — two Hermitian operators with the same trace against every density matrix are the same operator — the strongest statement follows at once: Δ\Delta EΛ(ρ)E_\Lambda(\rho) = 0 for every fine state ρ\rho if and only if DΛD_\Lambda = 0 as an operator identity, that is, if and only if Λ†(Hc)\Lambda^\dagger(H_c) = HfH_f exactly. Energy is preserved for every possible input under that one algebraic condition, never as a statistical…

Equation guide → · Article →
DΛ=0D_\Lambda = 0

Equation 53 · Evolutionary Physics

The Entry a Relabeling Cannot Write

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

Passive relabeling is one degenerate case; the other is simpler still. Let Λ\Lambda be the identity channel, Hc\mathcal H_c = Hf\mathcal H_f , HcH_c = HfH_f : no relabeling, no discarding, the coarse description simply is the fine one. Then trivially DΛD_\Lambda = 0 . Nothing in the paragraphs above required that; it follows on inspection. But the triviality is the point, because this is the operator-language shadow of the oldest and most secure fact the subject has. A system evolving under its own Hamiltonian, with nothing coarse-grained away and nothing relabeled, conserves that Hamiltonian’s own expectation value exactly, because the Hamiltonian generates its own time evolution and commutes with…

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