← Back to article

Equation 9 · Why Materials Fail: Fracture, Flaws and the Inspection Interval

What does this equation mean?

σf=2Eγsπa.\sigma_f = \sqrt{\frac{2E\gamma_s}{\pi a}}.

Read the formula alongside the article passage below. Each part has a deeper page with its role in the equation, the supporting passage and nearby citations.

Start with2Egamma_s
Divide bypi a
This relates tosigma_f
How to read the two sides of this formula. Follow the article passage for the meaning of each quantity.

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions. Read the equation part by part below; each part has a contextual explanation and a link to its mathematical background.

Read it piece by piece

σf\sigma_f

Symbol sigma_f

the critical remote stress.

Understand this part →

EE

Symbol E

the modulus.

Understand this part →

γs\gamma_s

Symbol gamma_s

the modulus e and surface energy.

Understand this part →

π\pi

Symbol pi

pi occurs below the fraction bar. The quantity above the bar is divided by this expression; zero is excluded as a denominator.

Understand this part →

aa

Symbol a

a is an input to the expression that computes the quantity on the left.

Understand this part →

=

=

The expressions on both sides represent the same quantity under the stated assumptions.

Understand this part →

See an illustrated explanation →
fraction

fraction

Divide the expression above the line by the one below it.

Understand this part →

See an illustrated explanation →
√

√

Take a square root.

Understand this part →

subscript

subscript

The lower label selects a particular version, component, or indexed member of the quantity. For example, x₀ and xₜ can be values at different positions.

Understand this part →

2Eγs2E\gamma_s

Numerator: 2Egamma_s

The complete quantity above the fraction bar.

Understand this part →

πa\pi a

Denominator: pi a

The complete quantity below the fraction bar; it must be nonzero for this division.

Understand this part →

How to interpret it

With a fixed numerator, increasing a nonzero denominator reduces the fraction. Read it with the definitions, units, and assumptions supplied by the article.

What the article says around this equation

Griffith’s criterion is an accounting statement. Extending a crack by a small increment releases stored elastic strain energy from the material that unloads around the new crack faces, and consumes energy in creating those faces. If the release exceeds the cost, extension is spontaneous and the crack runs. For a through-thickness crack of half-length a in a linear-elastic plate with modulus E and surface energy γs\gamma_s , the critical remote stress is σf=2Eγsπa\sigma_f = \sqrt{\frac{2E\gamma_s}{\pi a}}. The structure of this expression matters more than its coefficients. Strength scales as the inverse square root of flaw size, so halving the largest flaw raises strength by roughly forty per cent, and doubling it costs…
Read the full surrounding passage
Griffith’s criterion is an accounting statement. Extending a crack by a small increment releases stored elastic strain energy from the material that unloads around the new crack faces, and consumes energy in creating those faces. If the release exceeds the cost, extension is spontaneous and the crack runs. For a through-thickness crack of half-length a in a linear-elastic plate with modulus E and surface energy γs\gamma_s , the critical remote stress is σf=2Eγsπa\sigma_f = \sqrt{\frac{2E\gamma_s}{\pi a}}. The structure of this expression matters more than its coefficients. Strength scales as the inverse square root of flaw size, so halving the largest flaw raises strength by roughly forty per cent, and doubling it costs about thirty per cent. Strength is not an intrinsic property at all in this picture; it is a joint property of the material and its worst defect. Griffith’s own experimental work was on glass, where the assumption of negligible plastic deformation is nearly exact and the theory therefore lands cleanly [ 1 , 2 ] .

Read the equation in its article →

For background, read the article’s source list.

Return to Why Materials Fail: Fracture, Flaws and the Inspection Interval

See this formula across 1 published context →

Browse the mathematical compendium →