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Equation 4 · Part 7 · Why Materials Fail: Fracture, Flaws and the Inspection Interval

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σmax⁡=σ∞(1+2aρ).\sigma_{\max} = \sigma_\infty\left(1 + 2\sqrt{\frac{a}{\rho}}\right).
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Its job in the formula

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The passage around this formula

The first half of the argument is purely elastic and predates Griffith. An elliptical hole in a stressed plate does not merely remove load-bearing material; it redistributes the stress that would have passed through that material into the region around the hole’s sharpest curvature. For an elliptical flaw of half-length a and tip radius of curvature ρ\rho in a plate under remote tension σ∞\sigma_\infty , the peak stress at the tip is approximately σmax⁡=σ∞(1+2aρ)\sigma_{\max} = \sigma_\infty\left(1 + 2\sqrt{\frac{a}{\rho}}\right). Three things follow. First, the concentration depends on the flaw’s aspect ratio, not on its absolute size — a long shallow scratch and a short sharp one can concentrate stress equally. Second, as the tip sharpens toward an…

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