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Equation 42 · OpenAI Codex as a Software-Engineering System: Models, Harnesses, and Evidence

What does this equation mean?

accept⁡(s′)=1 ⁣[⋀i=1mvi(s′)=1]⋅u(s′),\operatorname{accept}(s') = \mathbb{1}\!\left[ \bigwedge_{i=1}^{m} v_i(s')=1 \right] \cdot u(s'),

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Inputs and operations1[ bigwedge_i=1^m v_i(s')=1 ] × u(s')
Result or conditionaccept(s')
How to read the two sides of this formula. Follow the article passage for the meaning of each quantity.

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions. Read the equation part by part below; each part has a contextual explanation and a link to its mathematical background.

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ss

Symbol s

s is an argument of the function-like quantity on the left; its role is set by that function’s stated inputs.

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ii

Symbol i

i is one factor in the product that computes the quantity on the left.

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mm

Symbol m

m is one factor in the product that computes the quantity on the left.

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viv_i

Symbol v_i

viv_i is one factor in the product that computes the quantity on the left.

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uu

Symbol u

required human or institutional authorization.

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=

=

The expressions on both sides represent the same quantity under the stated assumptions.

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multiplication

multiplication

Multiply the quantities on either side.

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subscript

subscript

The lower label selects a particular version, component, or indexed member of the quantity. For example, x₀ and xₜ can be values at different positions.

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superscript

superscript

A raised number can be a power. When it is a label or bound, it selects a case or the upper limit of a sum; the formula’s structure distinguishes these uses.

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How to interpret it

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What the article says around this equation

Suppose verification functions v1v_1,…\dots,vmv_m each observe a projection of changed state s' . Acceptance is accept⁡(s′)=1 ⁣[⋀i=1mvi(s′)=1]⋅u(s′)\operatorname{accept}(s') = \mathbb{1}\!\left[ \bigwedge_{i=1}^{m} v_i(s')=1 \right] \cdot u(s'). where u(s') represents required human or institutional authorization. Even if every viv_i passes, the false-accept probability is not zero because the conjunction covers only encoded properties. Correlated checks can repeat the same blind spot.

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Sources cited in the article section

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