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Equation 4 · Part 9 · Mechanistic Interpretability in 2035: Scenarios and Falsifiers

multiplication

R(t)=1 ⁣[A(t)≥a∗]⋅1 ⁣[S(t)≥s∗]R(t) = \mathbb{1}\!\left[A(t) \ge a^{*}\right] \cdot \mathbb{1}\!\left[S(t) \ge s^{*}\right]
multiplication

What this part means

Multiply the quantities on either side.

Its job in the formula

Multiply the quantities on either side.

The passage around this formula

Whether interpretability evidence becomes admissible for a safety certification is not a third axis; it is what the other two jointly produce, and the joint requirement is a conjunction rather than an average. Write A(t) for the share of a frontier model’s decision-relevant behaviour with a validated, causally checked account — Circuit Tracing’s own figures are the best public anchor for where A(t) sits today [ 2 ] — and S(t) for the share of published interpretability results built on a method that has cleared an agreed, cross-lab benchmark rather than a proxy metric of the kind SAEBench found unreliable [ 10 ] . A regulator or a court asked to accept mechanistic evidence needs both a…

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Learn the underlying idea

Multiplication scales one quantity by another. A dot, a cross, or adjacent symbols can indicate a product.

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Sources cited in the surrounding passage

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