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Equation 80 · The Clock That Comes Back Wrong by Exactly Its Mass

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Δϕ=0\Delta\phi=0

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Inputs and operations0
Result or conditionΔphi
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Δϕ\Delta\phi

Symbol Δphi

Δphi is part of the quantity the equation computes from the expression on the right.

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=

=

The expressions on both sides represent the same quantity under the stated assumptions.

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change

change

Capital delta attached to a quantity marks a difference between two values of that quantity; the article’s sign convention determines the order.

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What the article says around this equation

Two degenerate limits of the proper-time form confirm the derivative is doing the right job rather than hiding a division problem. As m→\to0 , Δ\Deltaϕ\phi→\to0 at every fixed Δ\Deltaτ\tau , so the slope — and therefore mopm_{\rm op} — vanishes identically: a massless worldline is exactly the case with no proper time to speak of in the first place, and the formula correctly returns nothing to divide. And if the two branches are held at equal proper time, Δ\Deltaτ\tau=0 , then Δ\Deltaϕ\phi=0 regardless of m ; a single measurement at that one setting is a 0/0 statement about mass, not a small number. Both limits are trivial once stated, and both are exactly why the estimator was built as a slope across a…
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Two degenerate limits of the proper-time form confirm the derivative is doing the right job rather than hiding a division problem. As m→\to0 , Δ\Deltaϕ\phi→\to0 at every fixed Δ\Deltaτ\tau , so the slope — and therefore mopm_{\rm op} — vanishes identically: a massless worldline is exactly the case with no proper time to speak of in the first place, and the formula correctly returns nothing to divide. And if the two branches are held at equal proper time, Δ\Deltaτ\tau=0 , then Δ\Deltaϕ\phi=0 regardless of m ; a single measurement at that one setting is a 0/0 statement about mass, not a small number. Both limits are trivial once stated, and both are exactly why the estimator was built as a slope across a family of loops rather than a ratio taken at one of them.

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