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Equation 33 · Part 7 · The Clock That Comes Back Wrong by Exactly Its Mass

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[X,Y]=imℏ b⋅v 1.[X,Y]=\frac{im}{\hbar}\,\mathbf b\cdot\mathbf v\,\mathbb 1.
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What this part means

The expressions on both sides represent the same quantity under the stated assumptions.

Its job in the formula

The equals sign connects the complete expression on the left with the complete expression on the right. Both sides must have compatible units.

The passage around this formula

That triviality is what makes the loop phase exact rather than approximate. Write X=-ib\mathbf b⋅\cdotP\mathbf P/ℏ\hbar and Y=-iv\mathbf v⋅\cdotK\mathbf K/ℏ\hbar . Their commutator is [X,Y]=imℏ b⋅v 1[X,Y]=\frac{im}{\hbar}\,\mathbf b\cdot\mathbf v\,\mathbb 1. Because [X,Y] is itself proportional to the identity, it commutes with both X and Y , so every higher term in the Baker–Campbell–Hausdorff expansion of eXe^XeYe^Ye−Xe^{-X}e−Ye^{-Y} vanishes identically, at all orders, with no small-loop approximation required:

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Learn the underlying idea

An equals sign says that the expression on its left and the expression on its right have the same value under the stated definitions and assumptions.

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