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Equation 33 · Part 10 · The Clock That Comes Back Wrong by Exactly Its Mass

Numerator: im

[X,Y]=imℏ b⋅v 1.[X,Y]=\frac{im}{\hbar}\,\mathbf b\cdot\mathbf v\,\mathbb 1.
imim

What this part means

The complete quantity above the fraction bar.

Its job in the formula

im occurs above the fraction bar. The numerator is divided by the entire denominator below it.

The passage around this formula

That triviality is what makes the loop phase exact rather than approximate. Write X=-ib\mathbf b⋅\cdotP\mathbf P/ℏ\hbar and Y=-iv\mathbf v⋅\cdotK\mathbf K/ℏ\hbar . Their commutator is [X,Y]=imℏ b⋅v 1[X,Y]=\frac{im}{\hbar}\,\mathbf b\cdot\mathbf v\,\mathbb 1. Because [X,Y] is itself proportional to the identity, it commutes with both X and Y , so every higher term in the Baker–Campbell–Hausdorff expansion of eXe^XeYe^Ye−Xe^{-X}e−Ye^{-Y} vanishes identically, at all orders, with no small-loop approximation required:

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Learn the underlying idea

A fraction a/b means a divided by b. The top number is the numerator; the bottom number is the denominator, and it cannot be zero.

Open the illustrated fractions: division written vertically guide →

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