Equation 113 · Part 2 · The Clock That Comes Back Wrong by Exactly Its Mass

Symbol s

\Delta\tau\approx1.090\times10^{-16}\,\mathrm s

s

What this part means

s is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

Its job in the formula

s is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

Full expressionSymbol sArticle meaning

The passage around this formula

…for a static height z in Earth’s field, so that holding two branches at a height difference $\Delta$ z for coordinate time T gives $\Delta$ $\tau$ $\approx$ g\, $\Delta$ z\,T/ $c^2$ . For $\Delta$ z=1\, $\mathrm m$ and T=1\, $\mathrm s$ , $\Delta$ $\tau$ $\approx$ 1.090 $\times$ 10^{-16}\, $\mathrm s$ . Pair this with a single-photon optical clock transition near 698\, $\mathrm{nm}$ , comparable to the transition used in strontium-lattice-clock proposals for this kind of experiment [ 11 , 13 ] , giving…

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