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Equation 9 · Part 7 · How Mechanistic Interpretability Research Is Actually Done

Symbol b_dec

LSAE(a)=∥a−a^∥22+λ∥z∥1,a^=Wdec z+bdec,z=ReLU ⁣(Wenc(a−bdec)+benc).\mathcal{L}_{\mathrm{SAE}}(a) = \lVert a - \hat a \rVert_2^2 + \lambda \lVert z \rVert_1, \qquad \hat a = W_{\mathrm{dec}}\, z + b_{\mathrm{dec}}, \qquad z = \mathrm{ReLU}\!\left(W_{\mathrm{enc}}(a - b_{\mathrm{dec}}) + b_{\mathrm{enc}}\right).
bdecb_{\mathrm{dec}}

What this part means

bdb_dec is one of the signed contributions combined to compute the quantity on the left.

Its job in the formula

bdb_dec is one of the signed contributions combined to compute the quantity on the left.

The passage around this formula

Sparse dictionary learning is the field’s answer, and it is a second and different act of extraction rather than a departure from the first: a sparse autoencoder is trained on the very same activation vectors the probe was reading, learning an overcomplete basis in which each vector is reconstructed as a sparse combination of dictionary elements. Writing a for the activation, z for its sparse code and a^\hat a for the reconstruction, LSAE(a)=∥a−a^∥22+λ∥z∥1,a^=Wdec z+bdec,z=ReLU ⁣(Wenc(a−bdec)+benc)\mathcal{L}_{\mathrm{SAE}}(a) = \lVert a - \hat a \rVert_2^2 + \lambda \lVert z \rVert_1, \qquad \hat a = W_{\mathrm{dec}}\, z + b_{\mathrm{dec}}, \qquad z = \mathrm{ReLU}\!\left(W_{\mathrm{enc}}(a - b_{\mathrm{dec}}) + b_{\mathrm{enc}}\right). The reconstruction term asks the dictionary to explain the activation; the ℓ1\ell_1 penalty asks it to explain it using as few active dictionary elements as possible at once. Cunningham and colleagues showed this produces directions…

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Sources cited in the surrounding passage

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