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Equation 131 · Part 13 · The Entry a Relabeling Cannot Write

Denominator: 2

Hc(t)=Hf+iℏ(iωr2σz)=ℏ(ω0−ωr)2σz,H_c(t) = H_f + i\hbar\Big(i\frac{\omega_r}{2}\sigma_z\Big) = \frac{\hbar(\omega_0 - \omega_r)}{2}\sigma_z,
22

What this part means

The complete quantity below the fraction bar; it must be nonzero for this division.

Its job in the formula

2 occurs below the fraction bar. The quantity above the bar is divided by this expression; zero is excluded as a denominator.

The passage around this formula

A single case makes the term concrete and ties it to a result nearly a century old. Let HfH_f = (ℏ\hbarω0\omega_0/2)σz\sigma_z , a spin precessing about a static field at its Larmor frequency, and let U(t) = exp⁡(iωrt σz/2)\exp(i\omega_r t\,\sigma_z/2) describe a frame rotating about the same axis at rate ωr\omega_r . Since U(t) is built entirely from σz\sigma_z , it commutes with HfH_f , so UHfH_fU†U^\dagger = HfH_f exactly and the bare conjugate is unchanged by the relabeling. But U˙\dot U U†U^\dagger = iωr\omega_rσz\sigma_z/2 exactly, giving Hc(t)=Hf+iℏ(iωr2σz)=ℏ(ω0−ωr)2σzH_c(t) = H_f + i\hbar\Big(i\frac{\omega_r}{2}\sigma_z\Big) = \frac{\hbar(\omega_0 - \omega_r)}{2}\sigma_z. the detuned Hamiltonian that governs spin precession in a frame rotating with an applied field — the identical construction I. I. Rabi used to analyze spin behavior in a…

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Learn the underlying idea

A fraction a/b means a divided by b. The top number is the numerator; the bottom number is the denominator, and it cannot be zero.

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Sources cited in the surrounding passage

These citations provide research context; check each source for the exact claim it supports.