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Equation 4 · Part 8 · AI Datacenter Interconnects in 2035: Scenarios, Signals, and Falsifiable Predictions

subtraction

R(t)=R0⋅2(t−t0)/TR(t) = R_0 \cdot 2^{(t - t_0)/T}
subtraction

What this part means

Subtract the following term or group from the preceding one. A leading minus marks a negative quantity.

Its job in the formula

Subtract the following term or group from the preceding one. A leading minus marks a negative quantity.

The passage around this formula

Analysis. A naive extrapolation makes the compressing cadence explicit rather than hiding it. Writing per-lane rate as a function of time, with R0R_0 the most recent standardised rate at time t0t_0 and T the assumed doubling period: R(t)=R0⋅2(t−t0)/TR(t) = R_0 \cdot 2^{(t - t_0)/T}. Anchoring at R0R_0 = 200 Gb/s per lane, t0t_0 = 2026 , and holding the most recently observed four-year doubling period fixed gives R(2035) = 200 ⋅\cdot 2^{9/4} ≈\approx 950 Gb/s per lane by 2035 — essentially a 1 Tb/s single electrical lane. That number is offered to be doubted, not believed. The assumption it encodes — that the doubling period keeps compressing on a fixed clock rather than lengthening as channel loss and signal-to-noise margin close…

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Learn the underlying idea

Addition combines quantities; subtraction measures the signed difference between them. Parentheses show what is combined before the rest of the expression is evaluated.

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Sources cited in the surrounding passage

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