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Equation 89 · Part 3 · No Particle Without a Cosigner

Symbol delta

Ddet(a, a+δa)  ≈  0.394 ∣δa∣a.D_{\rm det}(a,\, a+\delta a) \;\approx\; 0.394\, \frac{|\delta a|}{a}.
δ\delta

What this part means

delta occurs above the fraction bar. The numerator is divided by the entire denominator below it.

Its job in the formula

delta occurs above the fraction bar. The numerator is divided by the entire denominator below it.

The passage around this formula

…physical difference should produce a comparably graded disagreement rather than a large one. This is the sense in which the coefficient 0.394 is an exact result: it is the exact leading term of a convergent expansion in δ\delta a/a , obtained from an exact closed-form spectral shape by ordinary calculus, with the only numerical step being the solution of one transcendental equation to a stated precision. It is illustrative, not a report of anything measured, and it says nothing about accelerations that are not…

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Learn the underlying idea

A variable is a named place for a value. Its letter is a local label: x can mean position in one formula and a data point in another.

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Sources cited in the article section

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