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Equation 89 · Part 1 · No Particle Without a Cosigner

Symbol D_rm det

Ddet(a, a+δa)  ≈  0.394 ∣δa∣a.D_{\rm det}(a,\, a+\delta a) \;\approx\; 0.394\, \frac{|\delta a|}{a}.
DdetD_{\rm det}

What this part means

well defined, it can be evaluated, and the cleanest case where it is well defined and non-trivial is a comparison between two accelerated trajectories, both with finite normalizable spectra, differing only slightly in acceleration.

Its job in the formula

DrD_rm det is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

Where the article explains it

How Far Two Signatories Can Drift Where DdetD_{\rm det} is well defined, it can be evaluated, and the cleanest case where it is well defined and non-trivial is a comparison between two accelerated trajectories, both with finite normalizable spectra, differing only slightly in acceleration.

The passage around this formula

This is the same trick used to derive Wien’s displacement law: because u\,g(u) rises from zero, passes through a single interior maximum, and falls back to zero, the integral of the absolute value of its derivative over all u is exactly twice that maximum, with no need to evaluate the integral directly. Finding the maximum of u\,g(u) = 24\,u2u^2/(e2πue^{2\pi u}-1) means solving e2πu(1−πu)e^{2\pi u}(1-\pi u)=1 , the same class of transcendental equation that fixes the peak of a Planck spectrum weighted by an extra power of frequency. Solved by Newton’s method to five-figure precision, the nontrivial root is u∗u^\ast ≈\approx 0.25363 , at which u∗u^\ast g(u∗u^\ast) ≈\approx 0.3937 . The leading-order sensitivity is…

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