Starting index or lower bound: 0

The passage around this formula

…the same textbook fact that says an unaccelerated atom in its ground state, coupled to the electromagnetic vacuum, never spontaneously jumps up in energy [ 6 ] . Consequently $\dot{\mathcal F}_{\rm inertial}(\Omega)$ = 0 identically for every $\Omega$>0 , not approximately, not in some limit — exactly zero. The normalization integral $\int_0^\infty$ $\dot{\mathcal F}_{\rm inertial}(\Omega')$\,d$\Omega$' is therefore also exactly zero, and $p_{\rm inertial}(\Omega)$ is 0/0 : undefined.

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