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Equation 50 · Part 4 · No Particle Without a Cosigner

fraction

F˙a(Ω)  ∝  Ωe2πcΩ/a−1,Ω>0,\dot{\mathcal F}_a(\Omega) \;\propto\; \frac{\Omega}{e^{2\pi c \Omega / a} - 1}, \qquad \Omega > 0,
fraction

What this part means

Divide the expression above the line by the one below it.

Its job in the formula

The expression above the fraction bar is divided by the complete expression below it. The denominator must not be zero.

The passage around this formula

The first check any new object owes the literature is that it reproduce the literature’s own answer in the case the literature has already solved. For a worldline held at constant proper acceleration a forever, coupled linearly to a massless scalar field in the ordinary vacuum, with the switching left on for all time, the Wightman function depends only on the proper-time separation and the standard Fourier transform is exact and textbook: the excitation-branch rate per unit proper time takes the Bose-Einstein form F˙a(Ω)  ∝  Ωe2πcΩ/a−1,Ω>0\dot{\mathcal F}_a(\Omega) \;\propto\; \frac{\Omega}{e^{2\pi c \Omega / a} - 1}, \qquad \Omega > 0. with the proportionality constant fixed by the detector’s coupling strength and dimension — irrelevant here, since it cancels the instant the spectrum is…

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Learn the underlying idea

A fraction a/b means a divided by b. The top number is the numerator; the bottom number is the denominator, and it cannot be zero.

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Sources cited in the surrounding passage

These citations provide research context; check each source for the exact claim it supports.