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Equation 50 · Part 2 · No Particle Without a Cosigner

Symbol Omega

F˙a(Ω)  ∝  Ωe2πcΩ/a−1,Ω>0,\dot{\mathcal F}_a(\Omega) \;\propto\; \frac{\Omega}{e^{2\pi c \Omega / a} - 1}, \qquad \Omega > 0,
Ω\Omega

What this part means

Omega is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

Its job in the formula

Omega is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

The passage around this formula

The first check any new object owes the literature is that it reproduce the literature’s own answer in the case the literature has already solved. For a worldline held at constant proper acceleration a forever, coupled linearly to a massless scalar field in the ordinary vacuum, with the switching left on for all time, the Wightman function depends only on the proper-time separation and the standard Fourier transform is exact and textbook: the excitation-branch rate per unit proper time takes the Bose-Einstein form F˙a(Ω)  ∝  Ωe2πcΩ/a−1,Ω>0\dot{\mathcal F}_a(\Omega) \;\propto\; \frac{\Omega}{e^{2\pi c \Omega / a} - 1}, \qquad \Omega > 0. with the proportionality constant fixed by the detector’s coupling strength and dimension — irrelevant here, since it cancels the instant the spectrum is…

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Sources cited in the surrounding passage

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