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Equation 10 · Part 9 · No Particle Without a Cosigner

=

Fx(Ω)=∫dτ dτ′ χ(τ)χ(τ′) e−iΩ(τ−τ′) W[x(τ),x(τ′)],\mathcal F_x(\Omega) = \int d\tau\, d\tau'\, \chi(\tau)\chi(\tau')\, e^{-i\Omega(\tau-\tau')}\, W\big[x(\tau), x(\tau')\big],
=

What this part means

The expressions on both sides represent the same quantity under the stated assumptions.

Its job in the formula

The equals sign connects the complete expression on the left with the complete expression on the right. Both sides must have compatible units.

The passage around this formula

The detector, not the mode decomposition, is the object this article works with, for a reason that matters later: a detector’s response is what an experiment can actually report, while “the Bogoliubov coefficients of the true vacuum” is not the kind of thing any apparatus reads off a dial. The response functional for a pointlike, linearly coupled two-level (Unruh-DeWitt) detector on worldline x(τ\tau) , parametrized by its own proper time τ\tau , with energy gap Ω\Omega and switching function χ(τ)\chi(\tau) controlling when the interaction is on, is Fx(Ω)=∫dτ dτ′ χ(τ)χ(τ′) e−iΩ(τ−τ′) W[x(τ),x(τ′)]\mathcal F_x(\Omega) = \int d\tau\, d\tau'\, \chi(\tau)\chi(\tau')\, e^{-i\Omega(\tau-\tau')}\, W\big[x(\tau), x(\tau')\big]. where W is the field’s two-point Wightman function evaluated along the trajectory [ 5 ] . Three things in this expression are…

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Learn the underlying idea

An equals sign says that the expression on its left and the expression on its right have the same value under the stated definitions and assumptions.

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Sources cited in the surrounding passage

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