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Published equation contexts

s=ln⁡(ppost/(1−ppost)ppre/(1−ppre))s=\ln\left(\frac{p_{\mathrm{post}}/(1-p_{\mathrm{post}})}{p_{\mathrm{pre}}/(1-p_{\mathrm{pre}})}\right)

Why this formula appears here

A transfer rate above zero says a channel is associated with a trait. It does not yet say whether the trait is a faithful copy or a garbled one, and it says nothing about whether curators along the way made the trait more or less likely to survive into the next training corpus. Two further quantities complete the construction. The mutation rate μc\mu_c=1∣Mc+∣\frac{1}{|\mathcal{M}_c^+|}∑m∈Mc+\sum_{m\in\mathcal{M}_c^+}1\mathbb{1}[d(rmr_m,ρ\rho)>δ\delta] measures, among the trait-positive models in class c (the set Mc+\mathcal{M}_c^+ ), what fraction produce a response diverging from the seeded canonical form ρ\rho by more than a fixed threshold δ\delta under a declared distance function d : a high μc\mu_c says the…

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ppostp_{\mathrm{post}}

Symbol p_post

ppp_post occurs above the fraction bar. The numerator is divided by the entire denominator below it.

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pprep_{\mathrm{pre}}

Symbol p_pre

ppp_pre occurs below the fraction bar. The quantity above the bar is divided by this expression; zero is excluded as a denominator.

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ppost/(1−ppost)p_{\mathrm{post}}/(1-p_{\mathrm{post}})

Numerator: p_post/(1-p_post)

The complete quantity above the fraction bar.

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ppre/(1−ppre)p_{\mathrm{pre}}/(1-p_{\mathrm{pre}})

Denominator: p_pre/(1-p_pre)

The complete quantity below the fraction bar; it must be nonzero for this division.

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How to interpret it

With a fixed numerator, increasing a nonzero denominator reduces the fraction. Read it with the definitions, units, and assumptions supplied by the article.

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Published contexts (1)

A symbol can carry a different meaning in another article. Each occurrence keeps its own guide and term definitions.

s=ln⁡(ppost/(1−ppost)ppre/(1−ppre))s=\ln\left(\frac{p_{\mathrm{post}}/(1-p_{\mathrm{post}})}{p_{\mathrm{pre}}/(1-p_{\mathrm{pre}})}\right)

Equation 34 · Evolutionary AI

A Chatbot Confessed to Being Built by a Company That Never Trained It

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

A transfer rate above zero says a channel is associated with a trait. It does not yet say whether the trait is a faithful copy or a garbled one, and it says nothing about whether curators along the way made the trait more or less likely to survive into the next training corpus. Two further quantities complete the construction. The mutation rate μc\mu_c=1∣Mc+∣\frac{1}{|\mathcal{M}_c^+|}∑m∈Mc+\sum_{m\in\mathcal{M}_c^+}1\mathbb{1}[d(rmr_m,ρ\rho)>δ\delta] measures, among the trait-positive models in class c (the set Mc+\mathcal{M}_c^+ ), what fraction produce a response diverging from the seeded canonical form ρ\rho by more than a fixed threshold δ\delta under a declared distance function d : a high μc\mu_c says the…

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