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r:=[I−B(B⊤C−1B)+B⊤C−1]yr := \left[I - B\left(B^\top C^{-1}B\right)^{+}B^\top C^{-1}\right] y

Why this formula appears here

A tempting shortcut suggests itself immediately: pick any closed loop of clocks and sum the edge readings around it. If the sum fails to return to zero, something has broken the idea that a single scalar potential — curved or otherwise — assigns each clock one honest number. Formally, define the fitted residual r:=[I−B(B⊤C−1B)+B⊤C−1]yr := \left[I - B\left(B^\top C^{-1}B\right)^{+}B^\top C^{-1}\right] y. the part of y that weighted least squares could not explain with any node potential at all. It is tempting to read a nonzero r as curvature declaring itself. That reading is wrong, and the reason is worth deriving rather than waving at.

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Published contexts (1)

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r:=[I−B(B⊤C−1B)+B⊤C−1]y,r := \left[I - B\left(B^\top C^{-1}B\right)^{+}B^\top C^{-1}\right] y,

Equation 30 · Evolutionary Physics

The Bend an Elevator Cannot Fake

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

A tempting shortcut suggests itself immediately: pick any closed loop of clocks and sum the edge readings around it. If the sum fails to return to zero, something has broken the idea that a single scalar potential — curved or otherwise — assigns each clock one honest number. Formally, define the fitted residual r:=[I−B(B⊤C−1B)+B⊤C−1]yr := \left[I - B\left(B^\top C^{-1}B\right)^{+}B^\top C^{-1}\right] y. the part of y that weighted least squares could not explain with any node potential at all. It is tempting to read a nonzero r as curvature declaring itself. That reading is wrong, and the reason is worth deriving rather than waving at.

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