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nmax⁡≈ln⁡τln⁡qn_{\max} \approx \frac{\ln \tau}{\ln q}

Why this formula appears here

so the horizon that can be sustained at a target success rate τ\tau is nmax⁡≈ln⁡τln⁡qn_{\max} \approx \frac{\ln \tau}{\ln q}. The derivative of nmax⁡n_{\max} with respect to q is steep near q = 1 , which is the good news — small per-step gains buy disproportionate horizon. The bad news is the same expression read the other way: sustaining an order of magnitude more steps requires driving per-step error down by an order of magnitude, and every one of the six problems above is a term in that per-step error which scale is not reducing. Verification, calibration, and memory are precisely the mechanisms that break the exponential by resetting accumulated uncertainty. Without them, capability gains are spent buying a slowly lengthening…

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With a fixed numerator, increasing a nonzero denominator reduces the fraction. Its accuracy depends on the assumptions and range of use described in the article.

Published contexts (1)

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nmax⁡≈ln⁡τln⁡q.n_{\max} \approx \frac{\ln \tau}{\ln q}.

Equation 7 · Foundation Models

What We Still Cannot Do: Open Problems in Frontier Model Systems

This equation gives an approximation: it relates the quantities while allowing an approximation.

so the horizon that can be sustained at a target success rate τ\tau is nmax⁡≈ln⁡τln⁡qn_{\max} \approx \frac{\ln \tau}{\ln q}. The derivative of nmax⁡n_{\max} with respect to q is steep near q = 1 , which is the good news — small per-step gains buy disproportionate horizon. The bad news is the same expression read the other way: sustaining an order of magnitude more steps requires driving per-step error down by an order of magnitude, and every one of the six problems above is a term in that per-step error which scale is not reducing. Verification, calibration, and memory are precisely the mechanisms that break the exponential by resetting accumulated uncertainty. Without them, capability gains are spent buying a slowly lengthening…

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