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nmax⁡≈(B−T0)/tˉn_{\max} \approx (B - T_0)/\bar{t}

Why this formula appears here

Under a fixed context budget B , the largest catalogue that fits is roughly nmax⁡n_{\max} ≈\approx (B - T0T_0)/tˉ\bar{t} . The model is a reasonable first approximation, and it is also the assumption a tenfold per-tool variance directly undermines: tˉ\bar t is not a constant of the tool, it is a property of how verbosely that tool’s schema and description happen to be written, which is an editorial choice rather than a physical fact about the function. A recent controlled study of exactly this trade-off tested fourteen models from 1.5B to 32B parameters plus one frontier API model across 6,566 controlled tool calls at three context budgets, and found that at an 8K-token budget uncompressed JSON schemas…

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nmax⁡n_{\max}

Symbol n_max

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nmax⁡≈(B−T0)/tˉn_{\max} \approx (B - T_0)/\bar{t}

Equation 11 · AI Infrastructure

Measuring Tool Protocols and the Model Context Protocol: Evidence, Benchmarks, and Uncertainty

This equation gives an approximation: it relates the quantities while allowing an approximation.

Under a fixed context budget B , the largest catalogue that fits is roughly nmax⁡n_{\max} ≈\approx (B - T0T_0)/tˉ\bar{t} . The model is a reasonable first approximation, and it is also the assumption a tenfold per-tool variance directly undermines: tˉ\bar t is not a constant of the tool, it is a property of how verbosely that tool’s schema and description happen to be written, which is an editorial choice rather than a physical fact about the function. A recent controlled study of exactly this trade-off tested fourteen models from 1.5B to 32B parameters plus one frontier API model across 6,566 controlled tool calls at three context budgets, and found that at an 8K-token budget uncompressed JSON schemas…

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