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ϕ,ij+ϕ,iϕ,j\phi_{,ij}+\phi_{,i}\phi_{,j}

Why this formula appears here

Check it against the elevator directly: ϕ\phi = ln⁡(1+gZ/c2)\ln(1+gZ/c^2) gives ϕ\phi' = (g/c2c^2)/U and ϕ\phi'' = -(g/c2c^2)^2/U2U^2 = -(ϕ\phi')^2 exactly, for every Z , not merely at leading order. The bracket ϕ,ij\phi_{,ij}+ϕ,i\phi_{,i}ϕ,j\phi_{,j} vanishes identically, and so does RiR^i{}_{0j0} — confirming, by direct calculation rather than appeal to intuition, that a uniformly accelerated frame carries exactly zero curvature no matter how large its slope g becomes. The naive second difference of ln⁡\ln U alone, without the quadratic correction, does not vanish in this case — a fact worth stating plainly, because it is exactly the trap a network audit could fall into if it used ϕ,ij\phi_{,ij} by itself as its curvature signal.

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ϕ,ij\phi_{,ij}

Symbol phi_,ij

phi_,ij is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

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ϕ,i\phi_{,i}

Symbol phi_,i

phi_,i is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

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ϕ,j\phi_{,j}

Symbol phi_,j

phi_,j is a part of this expression. Its role is fixed by the surrounding article and by the operations shown in the formula.

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Published contexts (1)

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ϕ,ij+ϕ,iϕ,j\phi_{,ij}+\phi_{,i}\phi_{,j}

Equation 95 · Evolutionary Physics

The Bend an Elevator Cannot Fake

This mathematical expression combines the displayed quantities; its precise role follows from the surrounding article text.

Check it against the elevator directly: ϕ\phi = ln⁡(1+gZ/c2)\ln(1+gZ/c^2) gives ϕ\phi' = (g/c2c^2)/U and ϕ\phi'' = -(g/c2c^2)^2/U2U^2 = -(ϕ\phi')^2 exactly, for every Z , not merely at leading order. The bracket ϕ,ij\phi_{,ij}+ϕ,i\phi_{,i}ϕ,j\phi_{,j} vanishes identically, and so does RiR^i{}_{0j0} — confirming, by direct calculation rather than appeal to intuition, that a uniformly accelerated frame carries exactly zero curvature no matter how large its slope g becomes. The naive second difference of ln⁡\ln U alone, without the quadratic correction, does not vanish in this case — a fact worth stating plainly, because it is exactly the trap a network audit could fall into if it used ϕ,ij\phi_{,ij} by itself as its curvature signal.

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