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Published equation contexts

pass@⁡k=1−(1−p)k\operatorname{pass@}k=1-(1-p)^k

Why this formula appears here

The sampling result made the search interpretation explicit. If independent candidates have success probability p , the chance of at least one success among k is pass@⁡k=1−(1−p)k\operatorname{pass@}k=1-(1-p)^k. Real samples are not independent and the paper used estimators appropriate to its setup, but the conceptual point holds: model probability plus an evaluator can search a program space. Without a reliable selector, many candidates become review burden.

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pass@⁡k=1−(1−p)k.\operatorname{pass@}k=1-(1-p)^k.

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This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

The sampling result made the search interpretation explicit. If independent candidates have success probability p , the chance of at least one success among k is pass@⁡k=1−(1−p)k\operatorname{pass@}k=1-(1-p)^k. Real samples are not independent and the paper used estimators appropriate to its setup, but the conceptual point holds: model probability plus an evaluator can search a program space. Without a reliable selector, many candidates become review burden.

Meanings in this article

  • pp: the success probability.
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