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Published equation contexts

S=⌊(⌊(2B+I+⌊E/4⌋)⋅L100⌋+5)⋅N⌋S = \left\lfloor \left( \left\lfloor (2B+I+\lfloor E/4 \rfloor) \cdot \frac{L}{100} \right\rfloor + 5 \right) \cdot N \right\rfloor

Why this formula appears here

Since Generation III, every non-HP stat in a modern Pokémon game is produced by one rule: take twice the species’ base stat, add its individual value (an inherited number from 0 to 31, effectively fixed for a competitively bred Pokémon [ 4 ] ), add the floor of its invested effort value divided by four, scale by level over 100 and round down, add five, then multiply by a nature coefficient of 0.9, 1.0, or 1.1 and round down again [ 1 ] : S=⌊(⌊(2B+I+⌊E/4⌋)⋅L100⌋+5)⋅N⌋S = \left\lfloor \left( \left\lfloor (2B+I+\lfloor E/4 \rfloor) \cdot \frac{L}{100} \right\rfloor + 5 \right) \cdot N \right\rfloor. HP uses the same inner term but a different outer shell, adding the Pokémon’s level plus ten instead of multiplying by a nature:

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How to interpret it

With a fixed numerator, increasing a nonzero denominator reduces the fraction. Read it with the definitions, units, and assumptions supplied by the article.

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Published contexts (1)

A symbol can carry a different meaning in another article. Each occurrence keeps its own guide and term definitions.

S=⌊(⌊(2B+I+⌊E/4⌋)⋅L100⌋+5)⋅N⌋S = \left\lfloor \left( \left\lfloor (2B+I+\lfloor E/4 \rfloor) \cdot \frac{L}{100} \right\rfloor + 5 \right) \cdot N \right\rfloor

Equation 1 · Game-Mechanic Economics

The EV Formula Is an Exact Production Function Trainers Solved by Accident

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

Since Generation III, every non-HP stat in a modern Pokémon game is produced by one rule: take twice the species’ base stat, add its individual value (an inherited number from 0 to 31, effectively fixed for a competitively bred Pokémon [ 4 ] ), add the floor of its invested effort value divided by four, scale by level over 100 and round down, add five, then multiply by a nature coefficient of 0.9, 1.0, or 1.1 and round down again [ 1 ] : S=⌊(⌊(2B+I+⌊E/4⌋)⋅L100⌋+5)⋅N⌋S = \left\lfloor \left( \left\lfloor (2B+I+\lfloor E/4 \rfloor) \cdot \frac{L}{100} \right\rfloor + 5 \right) \cdot N \right\rfloor. HP uses the same inner term but a different outer shell, adding the Pokémon’s level plus ten instead of multiplying by a nature:

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