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Cstandardized=M+NC_{\text{standardized}} = M + N

Why this formula appears here

separate integrations, because nothing built for one pair transfers to any other. A protocol that both sides implement exactly once instead collapses this to Cstandardized=M+NC_{\text{standardized}} = M + N. The assumption a shared protocol is betting on is that the fixed cost of building and maintaining the standard itself is smaller than the integrations it removes, and that those removed integrations were genuinely redundant rather than differently necessary. When M and N are both large and still growing, the gap between M ×\times N and M + N dominates every other consideration; when either is small — a single application talking to a handful of tools it controls — a bespoke integration can still be cheaper than…

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CstandardizedC_{\text{standardized}}

Symbol C_standardized

CsC_standardized is part of the quantity the equation computes from the expression on the right.

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Published contexts (1)

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Cstandardized=M+N.C_{\text{standardized}} = M + N.

Equation 4 · AI Infrastructure

How AI Models Learned to Use Tools: A Protocol History

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions.

separate integrations, because nothing built for one pair transfers to any other. A protocol that both sides implement exactly once instead collapses this to Cstandardized=M+NC_{\text{standardized}} = M + N. The assumption a shared protocol is betting on is that the fixed cost of building and maintaining the standard itself is smaller than the integrations it removes, and that those removed integrations were genuinely redundant rather than differently necessary. When M and N are both large and still growing, the gap between M ×\times N and M + N dominates every other consideration; when either is small — a single application talking to a handful of tools it controls — a bespoke integration can still be cheaper than…

Meanings in this article

  • MM: the when.
  • NN: both large and still growing, the gap between M ×\times N and M + N dominates every other consideration.
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