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Equation 26 · Part 4 · Why Average Success Rate Hides the Failures That Matter Most

fraction

n≈kqτn \approx \frac{k}{q_\tau}
fraction

What this part means

Divide the expression above the line by the one below it.

Its job in the formula

The expression above the fraction bar is divided by the complete expression below it. The denominator must not be zero.

The passage around this formula

​ , so getting a usably precise estimate — a relative error in the neighbourhood of 20 to 25 percent, comparable to observing on the order of twenty events — requires n≈kqτn \approx \frac{k}{q_\tau}. trials in total. This is where the arithmetic becomes unforgiving in a way the mean-difference case never does. Detecting a fixed three-percentage-point difference between two average success rates takes roughly the same, bounded number of trials — on the order of a thousand — regardless of how good either system actually is, because that calculation is about the spread of a difference, not the rarity of an event. Bounding or estimating a rare catastrophic-failure rate is different in kind: the required…

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Learn the underlying idea

A fraction a/b means a divided by b. The top number is the numerator; the bottom number is the denominator, and it cannot be zero.

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Sources cited in the surrounding passage

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