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Equation 10 · Part 13 · The Economics, Energy, and Physical Limits of Tool Protocols and the Model Context Protocol

Numerator: k(k+1)

B(k)=Δ∑i=1ki=Δ k(k+1)2.B(k) = \Delta \sum_{i=1}^{k} i = \Delta\,\frac{k(k+1)}{2}.
k(k+1)k(k+1)

What this part means

The complete quantity above the fraction bar.

Its job in the formula

k(k+1) occurs above the fraction bar. The numerator is divided by the entire denominator below it.

The passage around this formula

Model it simply. Suppose a session runs for k turns, and each turn adds on average Δ\Delta tokens of new tool result to a transcript that is resent in full on every request, because nothing is evicting or compressing it. The tokens billed on turn i include roughly iΔ\Delta tokens of accumulated result history, so the total billed across the whole session is B(k)=Δ∑i=1ki=Δ k(k+1)2B(k) = \Delta \sum_{i=1}^{k} i = \Delta\,\frac{k(k+1)}{2}. Doubling the length of a session does not double the bill; it roughly quadruples it, because the earlier results are being paid for again on every one of the later turns. This is not a hypothetical — it is the direct arithmetic consequence of the same design choice OpenAI documents for its own tool schemas: whatever is…

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Learn the underlying idea

A fraction a/b means a divided by b. The top number is the numerator; the bottom number is the denominator, and it cannot be zero.

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Sources cited in the surrounding passage

These citations provide research context; check each source for the exact claim it supports.