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Equation 13 · The Benchmarks That Don't Need the Image

What does this equation mean?

Pchance=(1k)NP_{\mathrm{chance}} = \left(\frac{1}{k}\right)^{N}

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Divide byk
This relates toP_chance
How to read the two sides of this formula. Follow the article passage for the meaning of each quantity.

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions. Read the equation part by part below; each part has a contextual explanation and a link to its mathematical background.

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PchanceP_{\mathrm{chance}}

Symbol P_chance

PcP_chance is part of the quantity the equation computes from the expression on the right.

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kk

Symbol k

k occurs below the fraction bar. The quantity above the bar is divided by this expression; zero is excluded as a denominator.

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NN

Symbol N

N is an input to the expression that computes the quantity on the left.

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=

=

The expressions on both sides represent the same quantity under the stated assumptions.

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fraction

fraction

Divide the expression above the line by the one below it.

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subscript

subscript

The lower label selects a particular version, component, or indexed member of the quantity. For example, x₀ and xₜ can be values at different positions.

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superscript

superscript

A raised number can be a power. When it is a label or bound, it selects a case or the upper limit of a sum; the formula’s structure distinguishes these uses.

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11

Numerator: 1

The complete quantity above the fraction bar.

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How to interpret it

With a fixed numerator, increasing a nonzero denominator reduces the fraction. Read it with the definitions, units, and assumptions supplied by the article.

What the article says around this equation

It is worth seeing precisely why an all-or-nothing rule across permutations is so stringent, and where the intuition needs a caveat. If a model’s answer on each rotated pass were an independent uniform guess among k options, the probability of passing all N rotations by chance would be Pchance=(1k)NP_{\mathrm{chance}} = \left(\frac{1}{k}\right)^{N}. which for a four-option item run through all four rotations is (1/4)^4 , under half a percent. That is not a real prediction of model behavior — actual models are not memoryless guessers, and a model with a fixed positional bias will do considerably worse than this floor once the correct answer rotates away from its favored slot, while a model with genuine content understanding will pass…
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It is worth seeing precisely why an all-or-nothing rule across permutations is so stringent, and where the intuition needs a caveat. If a model’s answer on each rotated pass were an independent uniform guess among k options, the probability of passing all N rotations by chance would be Pchance=(1k)NP_{\mathrm{chance}} = \left(\frac{1}{k}\right)^{N}. which for a four-option item run through all four rotations is (1/4)^4 , under half a percent. That is not a real prediction of model behavior — actual models are not memoryless guessers, and a model with a fixed positional bias will do considerably worse than this floor once the correct answer rotates away from its favored slot, while a model with genuine content understanding will pass reliably regardless of k or N . The independence assumption is a deliberate simplification, useful only for showing why the two behaviors CircularEval separates — answering from content, and answering from position — land so far apart in practice, exactly as the OpenFlamingo v2 result illustrates.

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