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Equation 8 · How Benchmark Contamination Actually Works in Agentic Evaluation

What does this equation mean?

passk(t)=∏i=1k1 ⁣[trial i on task t succeeds],\text{pass}^k(t) = \prod_{i=1}^{k} \mathbb{1}\!\left[\text{trial } i \text{ on task } t \text{ succeeds}\right],

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Inputs and operationsprod_i=1^k 1[trial i on task t succeeds]
Result or conditionpass^k(t)
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This equation states an equality: the expressions on both sides have the same value under the article’s assumptions. Read the equation part by part below; each part has a contextual explanation and a link to its mathematical background.

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kk

Symbol k

k appears in the bound of this product. The bound states where the repeated operation starts, ends, or which values it includes.

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tt

Symbol t

t is an argument of the function-like quantity on the left; its role is set by that function’s stated inputs.

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ii

Symbol i

i appears in the bound of this product. The bound states where the repeated operation starts, ends, or which values it includes.

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=

=

The expressions on both sides represent the same quantity under the stated assumptions.

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subscript

subscript

The lower label selects a particular version, component, or indexed member of the quantity. For example, x₀ and xₜ can be values at different positions.

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superscript

superscript

A raised number can be a power. When it is a label or bound, it selects a case or the upper limit of a sum; the formula’s structure distinguishes these uses.

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i=1i=1

Starting index or lower bound: i=1

This label says where the repeated addition, multiplication, or accumulation starts. Read its value or condition together with the article’s description of the index.

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kk

Ending index or upper bound: k

This label says where the repeated addition, multiplication, or accumulation stops. It sets the last term or end of the range.

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How to interpret it

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What the article says around this equation

tau-bench itself — the benchmark in which that first exploit was found — was built to move past shallow grading, simulating a multi-turn conversation between a user (played by a language model) and a tool-using agent, then scoring the conversation against the resulting database state, with a passks^k metric meant to capture reliability across repeated trials rather than a single lucky success [ 7 ] . The mechanism is worth stating precisely, because it is a real assumption passks^k makes, and the empty-response exploit breaks exactly it: passk(t)=∏i=1k1 ⁣[trial i on task t succeeds]\text{pass}^k(t) = \prod_{i=1}^{k} \mathbb{1}\!\left[\text{trial } i \text{ on task } t \text{ succeeds}\right]. averaged over tasks to produce the benchmark’s headline number. The metric is designed to punish an agent whose competence is real but…
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tau-bench itself — the benchmark in which that first exploit was found — was built to move past shallow grading, simulating a multi-turn conversation between a user (played by a language model) and a tool-using agent, then scoring the conversation against the resulting database state, with a passks^k metric meant to capture reliability across repeated trials rather than a single lucky success [ 7 ] . The mechanism is worth stating precisely, because it is a real assumption passks^k makes, and the empty-response exploit breaks exactly it: passk(t)=∏i=1k1 ⁣[trial i on task t succeeds]\text{pass}^k(t) = \prod_{i=1}^{k} \mathbb{1}\!\left[\text{trial } i \text{ on task } t \text{ succeeds}\right]. averaged over tasks to produce the benchmark’s headline number. The metric is designed to punish an agent whose competence is real but inconsistent across resampled trials — a stochastic policy with true per-trial success probability p has passk\text{pass}^k ≈\approx pkp^k , which falls quickly as k grows. But a policy whose output on a given task is deterministic — an empty response, always, regardless of sampling — produces the identical transcript on every trial, so

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