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Equation 9 · Part 15 · Embeddings and the Geometry of Similarity

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lim⁡d→∞E ⁣[Dmax⁡k−Dmin⁡kd1/k−1/2]=C⋅1(k+1)1/k12k+1,\lim_{d \to \infty} \mathbb{E}\!\left[ \frac{D_{\max}^{k} - D_{\min}^{k}}{d^{1/k - 1/2}} \right] = C \cdot \frac{1}{(k+1)^{1/k}} \sqrt{\frac{1}{2k+1}},
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What this part means

A raised number can be a power. When it is a label or bound, it selects a case or the upper limit of a sum; the formula’s structure distinguishes these uses.

Its job in the formula

A raised mark can be a power or an index. Its position and the surrounding notation determine which.

The passage around this formula

Aggarwal, Hinneburg and Keim then showed the rate depends on the norm. For uniform data under an LkL_k metric, the expected gap between the farthest and nearest distances scales as lim⁡d→∞E ⁣[Dmax⁡k−Dmin⁡kd1/k−1/2]=C⋅1(k+1)1/k12k+1\lim_{d \to \infty} \mathbb{E}\!\left[ \frac{D_{\max}^{k} - D_{\min}^{k}}{d^{1/k - 1/2}} \right] = C \cdot \frac{1}{(k+1)^{1/k}} \sqrt{\frac{1}{2k+1}}. with C constant, while typical distances themselves grow like d1/kd^{1/k} . Relative contrast therefore decays with dimension, and the constant shrinks as k rises — which is why they conclude that L1L_1 is preferable to L2L_2 in high dimensions, L2L_2 to L3L_3 , and that fractional norms preserve contrast better still [ 12 ] .

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An exponent tells how a base is used in multiplication. In x³, x is the base and 3 is the exponent: x³ = x × x × x.

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Sources cited in the surrounding passage

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