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Equation 80 · A Reference Frame Becomes Classical by Publishing Its Orientation

What does this equation mean?

Hint(n)=ℏΩ J⋅σ(n)2j,Un=exp⁡ ⁣(−iκJ⋅σ(n)2j),H_{\mathrm{int}}^{(n)} =\hbar\Omega\, \frac{\mathbf J\cdot\boldsymbol\sigma^{(n)}}{2j}, \qquad U_n=\exp\!\left(-i\kappa \frac{\mathbf J\cdot\boldsymbol\sigma^{(n)}}{2j}\right),

Read the formula alongside the article passage below. Each part has a deeper page with its role in the equation, the supporting passage and nearby citations.

Start withmathbf J × boldsymbolσ^(n)
Divide by2j
This relates toH_int^(n)
How to read the two sides of this formula. Follow the article passage for the meaning of each quantity.

This equation states an equality: the expressions on both sides have the same value under the article’s assumptions. Read the equation part by part below; each part has a contextual explanation and a link to its mathematical background.

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Hint(n)H_{\mathrm{int}}^{(n)}

Symbol H_int^(n)

the candidate rotationally invariant interaction.

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Ω\Omega

Symbol Omega

Omega is one of the signed contributions combined to compute the quantity on the left.

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JJ

Symbol J

J occurs above the fraction bar. The numerator is divided by the entire denominator below it.

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σ(n)\sigma^{(n)}

Symbol σ^(n)

σ^(n) occurs above the fraction bar. The numerator is divided by the entire denominator below it.

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jj

Symbol j

j occurs below the fraction bar. The quantity above the bar is divided by this expression; zero is excluded as a denominator.

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UnU_n

Symbol U_n

UnU_n is one of the signed contributions combined to compute the quantity on the left.

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ii

Symbol i

i occurs above the fraction bar. The numerator is divided by the entire denominator below it.

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κ\kappa

Symbol kappa

kappa is one of the signed contributions combined to compute the quantity on the left.

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=

=

The expressions on both sides represent the same quantity under the stated assumptions.

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fraction

fraction

Divide the expression above the line by the one below it.

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multiplication

multiplication

Multiply the quantities on either side.

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subscript

subscript

The lower label selects a particular version, component, or indexed member of the quantity. For example, x₀ and xₜ can be values at different positions.

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superscript

superscript

A raised number can be a power. When it is a label or bound, it selects a case or the upper limit of a sum; the formula’s structure distinguishes these uses.

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J⋅σ(n)\mathbf J\cdot\boldsymbol\sigma^{(n)}

Numerator: mathbf J × boldsymbolσ^(n)

The complete quantity above the fraction bar.

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2j2j

Denominator: 2j

The complete quantity below the fraction bar; it must be nonzero for this division.

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J⋅σ(n)\mathbf J\cdot\boldsymbol\sigma^{(n)}

Numerator: mathbf J × boldsymbolσ^(n)

The complete quantity above the fraction bar.

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2j2j

Denominator: 2j

The complete quantity below the fraction bar; it must be nonzero for this division.

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How to interpret it

With a fixed numerator, increasing a nonzero denominator reduces the fraction. Read it with the definitions, units, and assumptions supplied by the article.

What the article says around this equation

Let J\mathbf J be the spin- j angular-momentum operator and σ(n)\boldsymbol\sigma^{(n)} the Pauli vector for probe n . A candidate rotationally invariant interaction is Hint(n)=ℏΩ J⋅σ(n)2j,Un=exp⁡ ⁣(−iκJ⋅σ(n)2j)H_{\mathrm{int}}^{(n)} =\hbar\Omega\, \frac{\mathbf J\cdot\boldsymbol\sigma^{(n)}}{2j}, \qquad U_n=\exp\!\left(-i\kappa \frac{\mathbf J\cdot\boldsymbol\sigma^{(n)}}{2j}\right). where Ω\Omega has units of inverse seconds, interaction time τ\tau has seconds, and κ\kappa=Ω\Omegaτ\tau is dimensionless. The factor 2j is a declared normalization choice, not an inherited law. Alternative normalizations must be compared because they change the large- j limit if coupling strength is held fixed under different conventions.

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